[(x+3)(x+3)]+4=5

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Solution for [(x+3)(x+3)]+4=5 equation: 


Simplifying
[(x + 3)(x + 3)] + 4 = 5

Reorder the terms:
[(3 + x)(x + 3)] + 4 = 5

Reorder the terms:
[(3 + x)(3 + x)] + 4 = 5

Multiply (3 + x) * (3 + x)
[(3(3 + x) + x(3 + x))] + 4 = 5
[((3 * 3 + x * 3) + x(3 + x))] + 4 = 5
[((9 + 3x) + x(3 + x))] + 4 = 5
[(9 + 3x + (3 * x + x * x))] + 4 = 5
[(9 + 3x + (3x + x2))] + 4 = 5

Combine like terms: 3x + 3x = 6x
[(9 + 6x + x2)] + 4 = 5
[9 + 6x + x2] + 4 = 5

Remove brackets around [9 + 6x + x2]
9 + 6x + x2 + 4 = 5

Reorder the terms:
9 + 4 + 6x + x2 = 5

Combine like terms: 9 + 4 = 13
13 + 6x + x2 = 5

Solving
13 + 6x + x2 = 5

Solving for variable 'x'.

Reorder the terms:
13 + -5 + 6x + x2 = 5 + -5

Combine like terms: 13 + -5 = 8
8 + 6x + x2 = 5 + -5

Combine like terms: 5 + -5 = 0
8 + 6x + x2 = 0

Factor a trinomial.
(4 + x)(2 + x) = 0


Subproblem 1
Set the factor '(4 + x)' equal to zero and attempt to solve:

Simplifying
4 + x = 0

Solving
4 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + x = 0 + -4
x = 0 + -4

Combine like terms: 0 + -4 = -4
x = -4

Simplifying
x = -4

Subproblem 2
Set the factor '(2 + x)' equal to zero and attempt to solve:

Simplifying
2 + x = 0

Solving
2 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + x = 0 + -2
x = 0 + -2

Combine like terms: 0 + -2 = -2
x = -2

Simplifying
x = -2
Solution
x = {-4, -2}

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